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![[User Picture]](http://l-userpic.livejournal.com/27276650/6146006) | From: strspn Thu, 17-Mar-2005 12:59 PM (UTC)
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If you feel you have reached this recording in error, please recompile your kernel.... Oh, wait.
![[User Picture]](http://l-userpic.livejournal.com/62361522/385978) | From: pfrank Thu, 17-Mar-2005 12:59 PM (UTC)
!!!111!!! | (Link)
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That's eleven ones. Crazy.
![[User Picture]](http://l-userpic.livejournal.com/62361522/385978) | From: pfrank Thu, 17-Mar-2005 1:07 PM (UTC)
Re: wait, no.. | (Link)
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I see, the subject line was 11111111111, which doesn't actually happen until Sun, 5 Feb 2322 19:45:11 UTC. Clearly, the world ends at Eleventy O'Clock.
![[User Picture]](http://l-userpic.livejournal.com/5887295/515656) | From: jwz Thu, 17-Mar-2005 1:11 PM (UTC)
oops | (Link)
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Ten Four, er, Ten Eleven.
Clearly, it's the world's eleventy first birthday, eh?
See, it had to be a mistake -- everybody knows the world is going to end on 19 January 2038 at 03:14:07 GMT.
![[User Picture]](http://l-userpic.livejournal.com/42441487/232194) | From: uke Thu, 17-Mar-2005 1:32 PM (UTC)
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#!/usr/bin/env python
import time
while True:
t = time.time ()
print t
time.sleep (1.11 - t + int (t))
![[User Picture]](http://l-userpic.livejournal.com/50799921/940036) | From: wy1d Thu, 17-Mar-2005 1:36 PM (UTC)
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I just have an xterm up with
watch --interval 1 'date +%s'
watch(1) on FreeBSD is for snooping on other terminals.
while true; do date +%s; sleep 1; done
should do the trick just as well, at least under Bourne shell derivatives.
![[User Picture]](http://l-userpic.livejournal.com/42441487/232194) | From: uke Thu, 17-Mar-2005 1:40 PM (UTC)
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Yeah but then you don't get the fractional part!
![[User Picture]](http://l-userpic.livejournal.com/84225994/3256134) | From: duskwuff Thu, 17-Mar-2005 2:49 PM (UTC)
Even better. | (Link)
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#!/usr/bin/env python
import sys, time
count_to = 1111111111
divisions = 20.0
while True:
t = time.time()
ct = count_to - t
ch,ct = divmod(ct, 3600)
cm,cs = divmod(ct, 60)
print "\r%.2f (remaining: %dh %dm %.2fs)" % (t, ch, cm, cs),
sys.stdout.flush()
time.sleep(1.0 / divisions - t + int(t * divisions) / divisions)
#!/usr/bin/perl
use strict;
use warnings;
use Gtk2 -init;
use Glib qw(TRUE FALSE);
my $label = Gtk2::Label->new( scalar time );
$label->modify_font(
Gtk2::Pango::FontDescription->from_string( "Monospace Bold 72" )
);
Glib::Timeout->add( 250, sub { $label->set_text( scalar time ); TRUE; } );
my $window = Gtk2::Window->new();
$window->signal_connect( delete_event => sub { Gtk2->main_quit } );
$window->set(
title => 1111111111,
resizable => FALSE,
child => $label,
);
$window->show_all;
Gtk2->main;
...But this one goes to 11.
![[User Picture]](http://l-userpic.livejournal.com/36619306/3491067) | From: phoe6 Thu, 17-Mar-2005 1:55 PM (UTC)
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#!/bin/bash while [ $(date +%s) != 1111111111 ] do echo "Not Yet!" done
echo "Unix Time" date +%s
echo "on `date`"
echo "so we captured the history!"
exit 0
I remember celebrating 1000000000. The seconds, where do they go?
Up yours and your stupid decimal notation.
The next time we hit all 1s (in binary), it'll be the end of the world, aka Mon Jan 18 19:14:07 2038 PST.
Also, the last time we hit all 1s just happened on Jan 10. And the previous time was in 1987.
My eyes are bleeding from geek-ese.
This post and its subsequent comments needs subtitles, or at least director's commentary.
![[User Picture]](http://l-userpic.livejournal.com/33375591/55823) | From: jhf Fri, 18-Mar-2005 4:32 PM (UTC)
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Time on unix is counted internally as the number of seconds from Jan 1st 1970. It will overflow 32 bits on the aforementioned date in 2038.
Better, no?
Actually it is.
My BF had later put up his own post celebrating a whole bunch of ones.
...I felt like the last guy on the block with rotary dial. | |